Match the statements/expressions given in Column - I with the values given in Column – II
Column - I Column - II
Text Solution
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→ (q, s), → (p, r, s, t), → (t), → (r)
Sol. 2 sin 2 θ + sin 2 2 θ = 2
⇒ sin 2 2 θ = 2 cos 2 θ ⇒ 4sin 2 θ cos 2 θ = 2cos 2 θ
⇒ cos 2 θ = 0 or sin 2 θ =
⇒ cos θ = 0 or sin θ =
⇒ θ =
or 
⇒ f(x) =
cos 
possible points of discontinuity of
are
= n , n
I
⇒ x =
⇒ x =
,
,
, π
f (x) = 0 cos 0 = 0
f(x) = 1 cos 0 = 1
∴ discontinuous at x =
. Similarly discontinuous at x =
,
, π
V =
= π cubic units
+
+
= 
⇒
+
= –

⇒
= 
⇒ a 2 + b 2 + 2
.
= 3c 2
⇒ 2 + 2 cos θ = 3
⇒ cos θ = 
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