Consider a pyramid OPQRS located in the first octant (x ≥ 0, y ≥ 0, z ≥ 0) with O as origin, and OP and OR along the x-axis and the y-axis, respectively. The base OPQR of the pyramid is a square with OP = 3. The point S is directly above the mid point T of diagonal OQ such that TS = 3. Then
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(b,c,d)
Sol. 
S ≡ 
⇒ 
= 
⇒ 
= 
+ 
+ 3 
cos θ = 
= 
= 
= 
= 
⇒ 
x – y = λ ⇒ x = y ⇒ ⊥ (3, 0, 0) ⇒ 
RS → 
= λ ⇒ x = 
λ , y = – 
λ + 3, z = 3 λ
T distance ⇒ 
⇒ 
D = 
λ 2 + 
+ 9 λ 2 = 
λ 2 – 9 λ + 9 ⇒ λ = 
= 
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems