Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The base of the pyramid AOBC is an equilateral triangle OBC with each side equal to 4
. ' O ' is the origin of reference, AO is perpendicular to the plane of Δ OBC and
= 2 . Then find the cosine of the angle between the skew straight lines one passing through A and the mid point of OB and the other passing through 'O' and the mid point of BC.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.

Sol.

= 

cos θ = 
cos θ = 
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The position vectors of two points A and C are 9 – +7k and 7 – 2 + 7 respectively. The point o…
Match the following set of lines to the corresponding type :
Let be vectors of length 3, 4, 5 respectively. Let be perpendicular to , to and to . Then i…
Four coplanar forces are applied at a point O. Each of them is equal to k and the angle between two…
Taken on side of a triangle ABC, a point M such that = . A point N is taken on the side such t…
If 3 non zero vectors are such that = , = = 1; = 4 the angle between and is cos –1 then =…