Home Maths Vector Algebra General The base of the pyramid AOBC is an equilater…
Maths Vector Algebra General Subjective Type
Published on: August 14, 2026

The base of the pyramid AOBC is an equilateral triangle OBC with each side equal to 4 . ' O ' is the origin of reference, AO is perpendicular to the plane of Δ OBC and = 2 . Then find the cosine of the angle between the skew straight lines one passing through A and the mid point of OB and the other passing through 'O' and the mid point of BC.

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The correct answer is:
CHECK THE SOLUTION.

Sol.

=

cos θ =

cos θ =

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