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CGP EDU Academic Team
Published on: August 13, 2026
For any three positive real numbers a, b and c, 9(25a 2 + b 2 ) + 25(c 2 – 3ac) = 15b(3a + c), Then
Text Solution
Verified by ExpertsThe correct answer is:
B
Sol. 225a 2 + 9b 2 + 25c 2 – 75ac – 45ab – 15bc = 0
(15a) 2 + (3b) 2 + (5c) 2 – (15a)(3b) – (3b)(5c) – (15a) (5c) = 0
[(15a – 3b) 2 + (3b – 5c) 2 + (5c – 15a) 2 ] = 0
15a = 3b , 3b = 5c , 5c = 15a
5a = b , 3b = 5c , c = 3a
a = λ , b = 5 λ , c = 3 λ
a, c, b are in AP
b, c, a are in AP
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