Published by:
CGP EDU Academic Team
Published on: August 11, 2026
In how many ways fifteen different items may be given to A, B, C such that A gets 3, B gets 5 and remaining goes to C.
Text Solution
Verified by ExpertsThe correct answer is:
360360
(360360)
Sol. No. of ways 3 item can be given to A is 15 C 3
then no. of ways 5 item can be given to B is 12 C 5
Rest are given to C is 7 C 7
Hence total no. of ways if all item is given is
15 C 3 × 12 C 5 × 7 C 7 = 455 × 792 × 1 = 360360
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