Published by:
CGP EDU Academic Team
Published on: August 12, 2026
How many nine-digit numbers can be formed using the digits 2, 2, 3, 3, 5, 5, 8, 8, 8 so that the odd digits occupy even positions?
Text Solution
Verified by ExpertsThe correct answer is:
D
Even place
There are four even places and four odd digit number so total number of filling is 
rest are also occupy is 
ways
Hence total number of ways = 
= 60
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