There are m apples and n oranges to be placed in a line such that the two extreme fruits being both oranges. Let P denotes the number of arrangements if the fruits of the same species are different and Q the corresponding figure when the fruits of the same species are alike, then the ratio P/Q has the value equal to :
Text Solution
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For P → If same species are different
Total number of arragements is nP 2 . (m + n – 2) !
For Q → If same species are alike then number of arrangement is 
Hence 
= nP2 . m! . (n – 2)! = nP2 . mPm . (n – 2)!
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