Number of five digits numbers divisible by 3 that can be formed using the digits 0, 1, 2, 3, 4, 7 and 8 if, each digit is to be used atmost one is N then 
is equal to
Text Solution
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(93)
Sol. Number divisible by 3 if sum of digits divisible
case-I If 1 + 2 + 3 + 4 + 8 = 18 Number of ways = 120
case-II If 1 + 2 + 3 + 7 + 8 = 21 Number of ways = 120
case-III If 2 + 3 + 4 + 7 + 8 = 24 Number of ways = 120
case-IV If 1 + 2 + 0 + 4 + 8 = 15 Number of ways = 96
case-V If 1 + 2 + 0 + 7 + 8 = 18 Number of ways = 96
case-VI If 2 + 0 + 4 + 7 + 8 = 21 Number of ways = 96
case-VII If 0 + 1 + 3 + 4 + 7 = 15 Number of ways = 96
total number 744
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