Let A ={1, 2, 3,4, 5} and B ={1, 2, 3,4, 5,6}. Then the number of functions f: A 
B satisfying f(a)+f(b)= f(d)-1 is equal to........
Text Solution
Verified by Experts360
(360)
Given,
f(a) + f(b)+l = f(d)
f(a)+f(b) 
5 {as f(d) 
6|
Now taking cases we get,
Case , f(a)= 1 
f(b)={1, 2,3,4} 
4 mappings
Case , f(a)= 2 
f(b)={1, 2,3} 
3 mappings
Case , f(a)= 3 
f(b)={1, 2} 
2 mappings
Case , f(a)= 4 
f(b)={1} 
1 mappings
And f(5) & f(6) 
6 mapping each
So, total number of function will be=(4 + 3 + 2 + l)x6x6 = 360
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