Maths Definite Integral and Area Under Curves JEE Main 2023 - ( Area Under Curve ) Numeric Response
Published on: August 14, 2026

Let y = p(x) be the parabola passing through the points (-1, 0), (0, 1) and (1, 0). If the area of the region {(x, y): (x + 1) 2 + (y - 1) 2 1, y p(x)} is A, then 12( - 4A) is equal to________.

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The correct answer is:
16

(16)

Let, the parabola be y = ax 2 + bx + c,

Now given parabola is passing through (-1, 0), (0,1) & (1,0)

Now putting the value in the above equation of parabola we get,

a-b+ c = 0...... , c = 1 .... and a + b + c = 0 ... .

Now solving above three equations we get,

Parabola as y = 1 - x 2

Now area of region between y = 1 - x 2 and (x + 1) 2 + (y -1) 2 1 is given by,

Now from above diagram, required area will be,

Hence, 12( -4A) = 16

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