Let y = p(x) be the parabola passing through the points (-1, 0), (0, 1) and (1, 0). If the area of the region {(x, y): (x + 1) 2 + (y - 1) 2
1, y
p(x)} is A, then 12(
- 4A) is equal to________.
Text Solution
Verified by Experts16
(16)
Let, the parabola be y = ax 2 + bx + c,
Now given parabola is passing through (-1, 0), (0,1) & (1,0)
Now putting the value in the above equation of parabola we get,
a-b+ c = 0...... , c = 1 .... and a + b + c = 0 ... .
Now solving above three equations we get,
Parabola as y = 1 - x 2
Now area of region between y = 1 - x 2 and (x + 1) 2 + (y -1) 2
1 is given by,

Now from above diagram, required area will be,


Hence, 12(
-4A) = 16
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