If the solution curve of the differential equation (y - 2 log e x)dx + (x log e x 2 )dy = 0, x > 1 passes through the points 
and (e 4 , 
), then a is equal to
Text Solution
Verified by Experts3
(3)
Given,
(y-2log e x)dx + (xlog e x 2 )dy = 0, x > 1
2x lnx 
+ y = 2 ln x {where log e x = lnx}
Which is linear differential equation,
So, I.F = 
Now, solution of the equation is given by,
... (i)
Given, eq. (i) passes through point 
So, C = 
Hence, solution of differential equation will be,
Also given, above equation passes through point (e 4 , 
)
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