Let y = y(x) be a solution curve of the differential equation, (1- x 2 y 2 )dx = ydx + xdy, If the line x = 1 intersects the curve y = y(x) at y = 2 and the line x = 2 intersects the curve y = y(x) at y = 
, then a value of 
is
Text Solution
Verified by ExpertsB
Given,
(l -x 2 y 2 )dx = ydx + xdy
Now integrating both side we get,
Now given, y(a)= 2 so putting the value in above equation we get,
3 = e c e 2
Hence, the equation becomes 
Now finding y(b) so putting x = 2 in above equation we get,
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