The number of five-digit numbers, greater than 40000 and divisible by 5, which can be formed using the digits 0, 1, 3, 5, 7 and 9 without repetition, is equal to
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We need to find the number of 5 digit numbers greater than 40000 and divisible by 5.
Case I: Numbers start with 5.
Here if the number starts with 5 it should end with 0 to be divisible by 5.
Case II: Number starts with 7 and the last digit can have 0 or 5.
Case III: The number starts with 9 and the last digit should have 0 or 5.
Total numbers = 120.
Hence this is the correct option.
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