If the probability that the random variable X takes values x is given by P(X = x) = k(x + l) 3-x , x = 0,1,2,3,......, where k is a constant, then P(X 
2) is equal to
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Given,
The probability that the random variable X takes values x is given by P(X = x) = k(x + l)3 -x , x = 0,1,2,3,......, where k is a constant,
Now we know that,
P(X = 0) + P(x = 1) + P(x = 2) +.........= 1
Now finding,
….
….
Now on subtracting above two equation we get,
Hence 
Now finding,
P(X 
2) = P(b) + P(c) +......
P(X 
2) = 1 - P(0) - P(l)
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