Given,

a 1 , a 2 ,a 3 ,….be a G.P. of increasing positive numbers,

And the sum of its 6 th and 8 th terms be 2

So, a 6 + a 8 = 2

ar 5 + ar 7 = 2 .....

And the product of its 3 rd and 5 th terms be ,

So, a 3 .a 5 = a 2 - r 2 - r 4 =

Now from putting the value or ar 3 = in equation we get,

(r 2 + 3)(r 2 -2)=0

r 2 = 2

Now finding the value of 6(a 2 + a 4 )(a 4 + a 6 ), we get

= 6(ar + ar 3 ) (ar 3 + ar 5 )

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