A cubical block of mass 
and edge 
slides down a rough inclined plane of inclination 
with a uniform velocity. The torque of the normal force on the block about its centre has a magnitude
Text Solution
Verified by ExpertsD
Here, rigid body is moving with constant velocity, i.e. it is in mechanical equilibrium.
Since, the cubical block slides with a uniform velocity and does not topple.
Torque due to normal force 
Torque due to weight = Component of weight parallel to plane 
Perpendicular distance from lower face 
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