Home Maths Set Theory and Relations JEE Main 2025 Let . Let R be a relation on defined by i…
Maths Set Theory and Relations JEE Main 2025 Single Correct MCQ
Published on: August 14, 2026

Let . Let R be a relation on defined by if and only if . Let be the number of elements in R. Let and be the minimum number of elements required to be added in R to make it reflexive and symmetric relations, respectively. Then is equal to

A
11
B
12
C
14
D
13

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Text Solution

Verified by Experts
The correct answer is:
B

To solve the problem, we start by defining the set and the relation on set , where an element is related to (written as ) if and only if .

This leads us to the following pairs in the relation :

For , so is in .

For , so ( ) is in .

For , so (0,1) is in .

For , so is in .

For , so is in .

Thus, the relation consists of the pairs:

and there are elements in R.
Making the Relation Reflexive
A relation is reflexive if every element in the set relates to itself. Therefore, the missing reflexive pairs are:

Adding these three pairs will make the relation reflexive, so .

Making the Relation Symmetric
A relation is symmetric if whenever ( ) is in must also be in . Therefore, the missing symmetric pairs are:

Thus, we need to add these three pairs for symmetry, so .

Finally, we calculate the sum

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