Let 
be a function satisfying 
and 
. For this function 
, answer the following.
(i) If 
, then the minimum possible number of values of 
satisfying 
, for 
, is
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Replace 
by 
. Then 
Also, given 
From (1) and (2), 
Replace 
by 
. Then 
.
Hence, the period of 
is 16
(i) Given 
.
(ii) 
Hence, 
is symmetrical about 
.
Also, 
or 
or 
Hence, 
is symmetrical about 
.
(iii) If 1 is a period, then 
or 
which contradicts the given hypotheses that 
.
Therefore, 1 cannot be period of 
.
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