In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:
Text Solution
Verified by ExpertsNOT AVAILABLE
Given that,
Difference of f A and f B , 
f = 6 Hz
If tension decreases, 
decreases and becomes f’b.
Now, difference of f A and f B , 
f '= 7 Hz
f A - f B = 6 Hz
Now, since f A = 530 Hz
f B = 524 Hz
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems