Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Find out the solubility of Ni(OH) 2 in 0.1 M NaOH. Given that the ionic product of Ni(OH) 2 is 2 x 10 -15
Text Solution
Verified by ExpertsThe correct answer is:
NOT AVAILABLE
Product of concentrations of ions in product is known as Ionic product.
Ionic product 
2 x 10 -15 = s(0,1) 2
s = 2 x 10 -13
Solubility of Ni(OH) 2 = 2 x 10 -13 M
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale.
The pitc…
Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over …
An electron is accelerated from rest through a potential difference of V volt If the de Broglie wav…
In a certain region of space with volume 0.2 m 3 , the electric potential is found to be 5 V throug…
A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27°C.
Its density is : (R =…
The mean free path for a gas, with molecular diameter d and number density n can be expressed as :