Biology NEET Full Syllabus Mock Test 180 Questions New Syllabus Mock Test - 5 PCB Single Correct MCQ
Published on: August 14, 2026

A woman with two genes (one on each -chromosome) for haemophilia and one gene for color blindness on the -chromosome marries a normal man. How will the progeny be?

A
All sons are haemophilic and colorblind
B
All haemophilic and colorblind daughters
C
50% haemophilic, colorblind sons and 50% normal sons
D
haemophilic daughters and colorblind daughters

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Text Solution

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The correct answer is:
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Haemophilia and colour blindness both are recessive -linked traits. They express in males when present in single copy (heterozygous) but in females, they express only when present in homozygous condition.

Results

sons are colorblind and haemophilic.

sons are haemophilic only.

daughters are carrier for colour blindness and haemophilia.

daughters are carrier for haemophilia only.

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