A woman having genes for haemophilia on one 
chromosome and other gene for colourblindness on another X chromosome marries a normal man. The progeny will show
haemophilic colour-blind sons and 
normal sons. 
haemophilic daughters (carrier) and 
colour blind daughters (carrier). Text Solution
Verified by ExpertsB
Both haemophilia and colourblindness diseases are produced by a recessive gene which lies on the X-chromosomes. A woman having both genes for haemophilia on one X-chromosome and gene for colourblindness on another X -chromosome will have genotype 
.
Thus, progeny includes 50% haemophilic daughters (carrier) and 50% colourblind daughters (carrier).
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems