Published by:
CGP EDU Academic Team
Published on: August 13, 2026
A LCR circuit is at resonance for a capacitor C, inductance 
and resistance R. Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:
Text Solution
Verified by ExpertsThe correct answer is:
B
In resonance 
halved
I becomes doubled.
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