A cube having a side of 10 cm with unknown mass and 200 gm mass were hung
at two ends of an uniform rigid rod of 27 cm long. The rod along with masses was placed on a wedge keeping the distance between wedge point and 200 gm weight as 25 cm . Initially the masses were not at balance. A beaker is placed beneath the unknown mass and water is added slowly to it. At given point the masses were in balance and half volume of the unknown mass was inside the water.
(Take the density of unknown mass is more than that of the water, the mass did not absorb water and water density is 
.) The unknown mass is 
kg .
Text Solution
Verified by Experts3
(3)
Given, volume of block 
Let density of block 
mass of block 
Buoyant Force 
F.B.D. of blocks
Balancing torque about point O , we get
Hence, mass of block 
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