JEE Main - Previous Year Papers JEE MAIN 2026 JEE Mains 2 April 2026 Paper Shift -2 Single Correct MCQ
Published on: August 14, 2026

A mixture of carbon dioxide and oxygen has volume , temperature 300 K , pressure 100 kPa and mass 13.2 g . The number of moles of carbon dioxide and oxygen gases in the mixture respectively are .(Assume both carbon dioxide and oxygen gases behave like ideal gases) [ ]

A
0.15 and 0.18
B
0.25 and 0.08
C
0.21 and 0.12
D
0.13 and 0.20

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Text Solution

Verified by Experts
The correct answer is:
C

First, we determine the total number of moles ( ) in the mixture using the Ideal Gas Law: PV = nRT. Given the values:

• Pressure (P):

• Volume (V):

• Temperature (T): 300 K

• Gas Constant (R):

1. Mole equation:

2. Mass equation: (where 44 and 32 are the molar masses of and respectively)

3. Solve for individual moles

Using the first equation to express as , we substitute this into the mass equation:

Then, calculate :

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