Published by:
CGP EDU Academic Team
Published on: August 21, 2026
Arrange the following intermediates in the correct order as they appear in the metabolic pathway from glucose to the Krebs' cycle:
A
Glucose 6-phosphate
, , ,
, , ,
B
Pyruvic acid
,
A), , (E) , (E) , (E)
,
A), , (E) , (E) , (E)
C
Fructose 1,6 bisphosphate
, , , ,
, , , ,
D
Glyceraldehyde 3-phosphate
(E) Acetyl CoA Choose the correct sequence from the options given below: , (E) , , ,
(E) Acetyl CoA Choose the correct sequence from the options given below: , (E) , , ,
Text Solution
Verified by ExpertsThe correct answer is:
The correct sequence starts with the phosphorylation of glucose to form Glucose 6-phosphate , which is then converted to Fructose 1,6 bisphosphate . This molecule is split to form Glyceraldehyde 3-phosphate , which then follows the glycolytic pathway to form Pyruvic acid . Pyruvic acid is finally converted into Acetyl CoA (E), entering the Krebs' cycle.
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