Tension in rod of length L and mass M at a distance y from F, when the rod is acted on by two unequal forces F 1 and F 2 where (F 2 < F 1 ) at its ends is
Text Solution
Verified by ExpertsThe correct answer is:
A
Acceleration along F 1 ,
a = 
Mass of length y = m = 
y
If T is tension in this length, then
F 1 – T = ma = 
= (F 1 – F 2 ) y/L
∴ ∴ T = F 1 – (F 1 – F 2 ) y/L
or T = F 1 (1 – y/L) + F 2 (y/L)
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