Published by:
CGP EDU Academic Team
Published on: August 21, 2026
A woman having genes for haemophilia on one 
chromosome and other gene for colourblindness on another X chromosome marries a normal man. The progeny will show
A
haemophilic colour-blind sons and 
normal sons. B
haemophilic daughters (carrier) and 
colour blind daughters (carrier). C
All sons and daughters are haemophilic and colourblind.
D
Haemophilic and colour-blind daughters.
Text Solution
Verified by ExpertsThe correct answer is:
B
Both haemophilia and colourblindness diseases are produced by a recessive gene which lies on the X-chromosomes. A woman having both genes for haemophilia on one X-chromosome and gene for colourblindness on another X -chromosome will have genotype 
.
Thus, progeny includes 50% haemophilic daughters (carrier) and 50% colourblind daughters (carrier).
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