When two monochromatic lights of frequency, v and 
are incident on a photoelectric metal, their stopping potential becomes 
and V s respectively. The threshold frequency for this metal is :
v
v
Text Solution
Verified by Experts(i) ; (ii)
Given that,
Frequency of monochromatic light 1, v 1 = v
Stopping potential of metal 1, V 1 = V s /2
Frequency of monochromatic light 2, v 2 = v/2
Stopping potential of metal 1, V 2 = V s
Now,
According to Einstein's equation of photoelectric effect.
…(i)
…(ii)
* Language of question is wrongly framed. The values of stopping potentials should be interchanged.
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