1 g of water, of volume 1 cm 3 at 100°C, is converted into steam at same temperature under normal atmospheric pressure ( 
1x10 5 Pa). The volume of steam formed equals 1671 cm 3 . If the specific latent heat of vaporisation of water is 2256 J/g, the change in internal energy is,
Text Solution
Verified by Experts(i) W; (ii) By first law of thermodynamics
Given that,
Mass of water at 100° C, m 1 = 1 g
Volume of water, Vi = 1 cm 3
Latent heat of water, L 1 = 2256 J/g
Volume of steam, V 2 = 1671 cm 3
Now,
Q= Lx m
= 2256 x 1 = 2256J.........(i)
W= Px[V 2 -V 1 ]
= 1 x 10 5 [1671- 1] x 10 -6
= 1670x10 5 x10 -6
= 167J.........(ii)
By first law of thermodynamics:
Q = 
U + 
W
2256 = 
U + 167
U = 2089J
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