Published by:
CGP EDU Academic Team
Published on: August 23, 2026
Two positively charged particles 
and 
have been accelerated across the same potential difference of 200 keV as shown below.
[Given mass of 
and 
]
The DE Broglie wavelength of 
will be x times of 
. The value of x is 
(nearest integer)
Text Solution
Verified by ExpertsThe correct answer is:
2
(2) 
Here KE is same i.e. 200 k eV
So 
So 
.
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