The mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70. If the correct mean is 16, then the correct variance is equal to:
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No. of observations: - 50

Standard deviation 
Let incorrect observation is
& correct observation is
Given 
(given)

Now
Mean of correct observation is 16


eq. (ii) - eq. (i)






from (iii)



From (iv)




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