Calculate the value of the constant in the combined law of Boyle and Gay-Lussac for one gram-molecule of gas in calories and in CGS units.
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Sol. One gram-molecule of any gas at T 0 = 273º abs and a pressure of P 0 = 1 atm occupies a volume of V 0 = 22.4 litres. Therefore,
R = 
= 
l .atm/deg = 0.82 l .atm/deg
The answer can be obtained by simply changing the dimensions for the different systems of units.
R ≈ 1.9 cal/deg = 8.3 × 10 7 erg/deg.
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