Hard rubber has a dielectric constant of 2.8 and a dielectric strength (maximum electric field) of 18 x 10 6 volt/meter. If it is used as the dielectric material filling the full space in a parallel plate capacitor. Minimum area may the plates of the capacitor have in order that the capacitance be 7.0 x 10 -2 µF is equal to 
m 2 . What should be the value of n if capacitor be able to withstand a potential difference of 4000 volts. ( ∈ 0 = 
S.I unit)
Text Solution
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(5)
Sol. Let distance between the plates = d
18 × 10 6 × d = 4000
d = 
Now C = 
7.0 × 10 – 2 × 10 – 6 = 
Solving, We get A = 
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