A stone tied to one end of string 80 cm long is whirled in a horizontal circle with a constant speed. If stone makes 14 revolutions in 25 sec, the magnitude of acceleration of stone is :
Text Solution
Verified by ExpertsThe correct answer is:
B
Time period
=
=
= 1.79 sec
Now angular speed
ω =
=
= 3.51 rad/sec
Now magnitude of acceleration is given by
a = ω 2 I = (3.51) 2 × 80
= 985.6 cm/sec 2 = 996 cm/sec
2
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle moves in a circle of radius 1.0 cm at a speed given by v= 2.0 t where v is in cm/s and t…
A particle is moving along a circular path of radius 5 m with a uniform speed 5 ms – 1 . What is th…
On horizontal smooth surface a mass of 2 kg is whirled in a horizontal circle by means of a string …
Consider a case in which, the driver of a car travelling at a high speed suddenly sees a wall
at a …
A particle moves with deceleration along the circle of radius R so that at any
moment of time its t…
A particle A moves along a circle of radius so that its radius vector
relative to the fixed point…