A 0.095 gm sample of purified carbonate was dissolved in 50 ml of 0.1 M HCl and boiled to eliminate
. Back titration of excess HCl require 24.2 ml of 0.1 M NaOH. Identify carbonate.
Text Solution
Verified by ExpertsThe correct answer is:
B
Millimoles of excess
Millimoles of HCl reacted with Carbonate





(Carbonate will be
)
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