The oxide of a metal (R) can be reduced by the metal (P) and metal (R) can reduce the oxide of metal (Q). Then the decreasing order of the reactivity of metal (P), (Q) and (R) with oxygen is
A
B
P 
R 
Q
R Q C
R 
P 
Q
P Q
D
Q 
P 
R
P R
Text Solution
Verified by ExpertsThe correct answer is:
B
As R can reduce oxide of Q, so R is more reactive than Q.
P can reduce oxide of R so P is more reactive than R.
So, reactivity order is 
.
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