If dimensions of critical velocity 
of a liquid flowing through a tube are expressed as 
where 
and 
are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively then the values of 
and 
are given by
A
B
1, 1, 1
C
Text Solution
Verified by ExpertsThe correct answer is:
C
(given) (i) Writing the dimensions of various quantities in
(i), we get
Applying the principle of homogeneity of dimensions, we get
On solving, we get
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