A lens of focal length 'f' is cut along the diameter into two identical halves. In this process, a layer of the lens 't' in thickness is lost, then the halves are put together to form a composite lens. In between the focal plane & the composite lens, a narrow slit is placed very near the focal plane. The slit is emitting monochromatic light with wavelength λ . Behind the lens a screen is located at a distance L from it-
(i) Fringe width of interference pattern-
Text Solution
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Ans.
(i)
Sol.
= 
+ 
V = 
as U < f ∴ V = – Ve
(V) = 
m = 
I = 
× 
d = 2I – t = 
– t = 
D = L + |V|
= L + 
ω = fring width = 
= 
= 
as U = f
ω = 
(ii)
Sol. 
x = 
= 
× 
× 
= 
Length of interference zone = 2x = 
.
(iii)
Sol. Number of Maxima
= 
= 
= 
.
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