Suppose a particle, that carries a charge of magnitude q & has a mass 4 × 10 –15 kg, is moving in a region containing a uniform magnetic field 
= – 0.4 
Tesla. At any instant, velocity of the particle is 
= (8 
– 6 
+ 4 
) × 10 6 m/s & force acting on it has a magnitude 1.6 N.
(i) Magnitude of charge on the particle, q is –
Text Solution
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Ans.
(i)
Sol. F= q( 
× 
)
F= 10 6 × q (8 
– 6 
+ 4 
) × (–0.4) 
F= 10 6 × q [+ 3.2 
+ 2.4 
]
| F | = q × 10 6 
1.6 = q × 4 × 10 6
q= 0.4 × 10 –6 = 0.4 μ C
(ii)
Sol.
Resultant velocity = 10 × 10 6 in x-y plane circular motion of in x-y plane translational component along z-axis.
(iii)
Sol.
After 3T
its x & y coordinate will remain same
z-coordinate = 4 × 3T = 12T
T = 
, z-coordinate =1.884 m
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