A force
= (y 2 – x 2 + z 2 )
+ (3xy – 5z)
+ 4z
is applied on a particle. Find the work done by the force when the particle moves from the point (0, 0, 0) to the point (2, 4, 0) in the paths shown in figure.

Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol. The work done by a force
along a curve C is defined by the line integral.
W =
…... (i)
Substituting the force
, and dividing the integral into two parts, (0, 0) → (2,0) and (2, 0) → (2,4), we obtain
W =
+
…..(ii)
y is a constant in (0,0) → (2,0) (y = 0) and x is a constant in (2,0) → (2,4) (x = 2). Therefore,
W =
…...(iii)
We first write the line in parametric from using formula from analytic geometry:
=
=
= ts …...(iv)
Where x`,y and z are variables (here z
0) and (x 1 , y 1 , z 1 ) and (x 2 , y 2 , z 2 ) are two given points on the line (here (0, 0, 0) and (2, 4, 0). Substituting these points in the formula, we obtain:
…...(v)
We substitute in
, so that
= 12t 2
+ 24t 2
. Therefore,
W =
…...(vi)
(we used dx = 2dt and dy = 4dt).
We will use parameterization:
…...(vii)
So that the force is
(t) = (t 4 – t 2 )
– 3t 3
. Therefore,
W =
…...(viii)
Conclusion – The force is not conservative, as the work is dependent on the path taken.
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