The two pipes are submerged in sea water, arranged as shown in figure. Pipe A with length LA = 1.5 m and one open end, contains a small sound source that sets up the standing wave with the second lowest resonant frequency of that pipe. Sound from pipe A sets up resonance in pipe B, which has both ends open. The resonance is at the second lowest resonant frequency of pipe B. The length of the pipe B is:

Text Solution
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For pipe
, second resonant frequency is third harmonic thus 
For pipe
, second resonant frequency is second harmonic thus 
Equating 

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