The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is :
Text Solution
Verified by ExpertsThe correct answer is:
D
We should use parallel axis theorem

Moment of inertia of disc passing through its centre of gravity and perpendicular to its plane is
Ι AB = 
Using theorem of parallel axes, we have,
Ι CD = Ι AB + MR 2
= 
= 
Note : The role of moment of inertia in the study of rotational motion is analogous to that of mass in study of linear motion.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Four identical particles each of mass m are placed on x-y plane as shown. If I x , I y and I z are …
A disc of mass m and radius r lies in x-y plane with its centre at a distance 'a' from origin at (a…
Given a thin square lamina of a size a × a and mass M (see fig.)
Moment of inertia of a body is independent of the dimension of the body parallel to the axis of rot…
Figure shows a uniform rectangular sheet with . Moment of inertia of the sheet is maximum about
Which of the following graphs correctly represents the variation of moment of inertia of a thin ci…