A particle is projected at time t = 0 from a point P on the ground with a speed V 0 , at an angle of 45° to the horizontal. What is the magnitude of the angular momentum of the particle about P at time t= v 0 /g.
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
x = v 0 cos 45º × t = 
τ = mgx = 
= 
⇒ L = 
= 
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