A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4R is made from an iron plate thickness t/4. Then the relation between the moment of inertia Ι X and Ι Y is :
Text Solution
Verified by ExpertsThe correct answer is:
D
Mass of disc (X), mx = π R 2 t ρ
Where ρ = density of material of disc
∴ l X = 
m X R 2 = 
R 2 t ρ R 2
l X = 
πρ R 4 .......(i)
Again mass of disc (Y)
m y = π = (4R) 2 
ρ = 4 π R 2 t ρ
and l Y = 
m Y (4R 2 ) = 
4 π R 2 t ρ .16R 2
⇒ l Y = 32 π t ρ R 4 ......(ii)
∴ 
⇒ = 64
∴ l Y = 64 l x
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