A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of B = 0.15 tesla. If the resistance is 3 Ω Ω the force required to move the rod with a constant velocity of 2 m/sec is-
Text Solution
Verified by ExpertsThe correct answer is:
A
V = Bvl = 0.15 × 2 × 0.5 = 0.15 × 1
= 0.15 volt
F = Bil = 0.15 × 
× .5
= 75 × 10 -4 × .5
= 375 × 10 -5 = 3.75 × 10 -3 N.
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