The potential energy of a 2 kg particle, free to move along the x-axis is given b 
. The total mechanical energy of the particle is 2 J then, the maximum speed (in m s -1 ) is
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(1.5)
Total energy E T = 2 J It is fixed. For maximum speed, kinetic energy is maximum The potential energy
should, therefore, be minimum
or 
For V to be minimum, 
x(x 2 - 1) = 0 , or x = 0 , ±1
at x = 0, V(x) = 0
At x = ±l, 
(Kinetic energy) max = E T - V min
or 
(Kinetic energy) max 
or 
or 
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