Home Physics System of Particles Rotational Motion JEE Main 2023 A bullet of 10 g leaves the barrel of gun wi…
Physics System of Particles Rotational Motion JEE Main 2023 MCQ (Single Correct)

A bullet of 10 g leaves the barrel of gun with a velocity of 600 m s -1 . If the barrel of gun is 50 cm long and mass of gun is 3 kg, then value of impulse supplied to the gun will be:

A
6Ns
B
3Ns
C
36 Ns
D
12 Ns

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Text Solution

Verified by Experts
The correct answer is:
A

The formula to calculate the impulse (J) on the gun is given by

J = m(v-u) ...

where, m is the mass, u is the initial velocity and v is the final velocity of the bullet. Substitute the values of the known parameters into equation to calculate the required impulse.

= 6Ns

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