In Young’s double slits experiment, the position of 5 th bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is:
A
60 
m
m
B
48 
m
m
C
12 
m
m
D
36 
m
m
Text Solution
Verified by ExpertsThe correct answer is:
A
Given
D=1m
= 600x10 -9 m
n = 5
As 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The width of fringe is 2 mm on the screen in a double slit experiment for the light of wavelength o…
The ratio of intensities at two points P and Q on the screen in a Young's double slit experiment wh…
In a Young's double slit experiment, the ratio of amplitude of light coming from slits is 2 : 1. Th…
A single slit of width a is illuminated by a monochromatic light of wavelength 600 nm. The value of…
Given below are two statements :
Statement I : If the Brewster's angle for the light propagating fr…
In a Young's double slit experiment, two slits are illuminated with a light of wavelength 800 nm. T…