Match the List-I with List-II.
| List-I | (Electronic | configuration) |
| List-II | (Electroncgativity | of element) | ||||||||
List-I | |||||||||||||||
(Electronic | |||||||||||||||
configuration) | |||||||||||||||
List-II | |||||||||||||||
(Electroncgativity | |||||||||||||||
of element) | |||||||||||||||
A. | (i) | 3.04 | |||||||||||||
B. | (ii) | 2.58 | |||||||||||||
C. | (iii) | 3.98 | |||||||||||||
D. | (iv) | 3.44 |
Choose the correct answer from the options given below.
Text Solution
Verified by ExpertsC
Configuration | Element |
Fluorine (F) | |
Oxygen (O) | |
Nitrogen (N) | |
Sulphur (S) |
On moving down the group, atomic size increases and electronegativity decreases. While in period, electronegativity increases.
So, order will be
.
Hence, the correct match is A-(iii), B-(iv), C-(i), D-(ii).
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